X^2=25+8x

Solution for X^2=25+8x equation:

X^2=25+8X

We move all terms to the left:

X^2-(25+8X)=0

We add all the numbers together, and all the variables

X^2-(8X+25)=0

We get rid of parentheses

X^2-8X-25=0

a = 1; b = -8; c = -25;
Δ = b2-4ac
Δ = -82-4·1·(-25)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{41}}{2*1}=\frac{8-2\sqrt{41}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{41}}{2*1}=\frac{8+2\sqrt{41}}{2}
$